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question 4 10 pts g.gsr.6.3 (mc) find the value of x. image of a right …

Question

question 4
10 pts
g.gsr.6.3 (mc)
find the value of x.
image of a right triangle with legs 56 and 33, hypotenuse x
options:
x = 60
x = 65
x = 62
x = 70

Explanation:

Step1: Identify the triangle type

The triangle is a right triangle, so we use the Pythagorean theorem: \( a^2 + b^2 = c^2 \), where \( a = 56 \), \( b = 33 \), and \( c = x \).

Step2: Substitute values into the formula

Substitute \( a = 56 \) and \( b = 33 \) into the formula: \( 56^2 + 33^2 = x^2 \).
Calculate \( 56^2 = 3136 \) and \( 33^2 = 1089 \).
Then \( x^2 = 3136 + 1089 = 4225 \).

Step3: Solve for x

Take the square root of 4225: \( x = \sqrt{4225} = 65 \).

Answer:

x = 65