Question

question 1
10 pts
g.gsr.6.3 (lc)
in a right triangle, a = 10, b = 24, and c = ?. find the value of c.

c = 30
c = 35
c = 26
c = 25

Explanation:

Step1: Recall Pythagorean theorem

For a right triangle, \(a^2 + b^2 = c^2\) (where \(c\) is the hypotenuse).

Step2: Substitute values of \(a\) and \(b\)

Given \(a = 10\), \(b = 24\), so \(10^2 + 24^2 = c^2\).
Calculate \(10^2 = 100\), \(24^2 = 576\). Then \(100 + 576 = c^2\), so \(676 = c^2\).

Step3: Solve for \(c\)

Take the square root of both sides: \(c=\sqrt{676}=26\).

Answer:

c = 26 (the option with "c = 26")