Question

question 10 (1 point)
which compound is a constitutional isomer of the compound shown below?

( \begin{array} { c } { mathrm { ch } _ { 3 } } \\ { mathrm { ch } _ { 3 } - mathrm { c } - mathrm { ch } _ { 3 } } \\ { mathrm { ch } _ { 3 } } end{array} )
( \bigcirc ) a) methane
( \bigcirc ) b) butane
( \bigcirc ) c) propane
( \bigcirc ) d) pentane
( \bigcirc ) e) hexane

Explanation:

Constitutional isomers have the same molecular formula but different connectivity. The given compound is neopentane (\(C_5H_{12}\)). Pentane (\(C_5H_{12}\)) has the same molecular formula as neopentane but different connectivity (straight - chain vs branched). Methane (\(CH_4\)), butane (\(C_4H_{10}\)), propane (\(C_3H_8\)), and hexane (\(C_6H_{14}\)) have different molecular formulas.

Answer:

d) pentane