Question

question 10
identify the type of reaction for
reactants are given. phases of
identify the type of reaction.
k₂s(aq) + cacl₂(aq) → 2 kcl + cas
cl₂(aq) + 2 nabr(aq) → 2 nacl + br₂
h₂so₄(aq) + 2 lioh(aq) → li₂so₄ + 2 h₂o

Explanation:

Step1: Analyze the first reaction \(K_2S(aq)+CaCl_2(aq)\to 2KCl + CaS\)

In this reaction, two ionic compounds \(K_2S\) and \(CaCl_2\) exchange their ions (\(K^+\) with \(Ca^{2+}\) and \(S^{2 -}\) with \(Cl^-\)). The product \(CaS\) is a precipitate (assuming it forms a solid in the context of the reaction). This is characteristic of a precipitation reaction.

Step2: Analyze the second reaction \(Cl_2(aq)+2NaBr(aq)\to 2NaCl + Br_2\)

Here, \(Cl_2\) is reduced (\(Cl\) in \(Cl_2\) has an oxidation state of \(0\) and in \(NaCl\) it is \(- 1\)) and \(Br^-\) in \(NaBr\) is oxidized (\(Br\) in \(NaBr\) has an oxidation state of \(-1\) and in \(Br_2\) it is \(0\)). Since there is a transfer of electrons (oxidation - reduction), this is an oxidation - reduction reaction.

Step3: Analyze the third reaction \(H_2SO_4(aq)+2LiOH(aq)\to Li_2SO_4 + 2H_2O\)

\(H_2SO_4\) is an acid (\(H^+\) donor) and \(LiOH\) is a base (\(OH^-\) donor). They react to form a salt (\(Li_2SO_4\)) and water. This is the classic form of an acid - base reaction.

Answer:

1. precipitation
2. oxidation - reduction
3. acid - base