Question

question 10
a fisherman reels in a fish by exerting a tension force on the fish in the upward direction. the fish has a mass of 1.3 kilograms. if the fisherman applies an upward tension force equal to 23 newtons, what must be the acceleration of the fish in the upward direction?

Explanation:

Step1: Calculate the weight of the fish

The weight of an object is given by \(W = mg\), where \(m = 1.3\space kg\) and \(g=9.8\space m/s^{2}\). So, \(W=1.3\times9.8 = 12.74\space N\)

Step2: Apply Newton's second law \(F_{net}=ma\)

The net force \(F_{net}=T - W\), where \(T = 23\space N\) and \(W = 12.74\space N\). So, \(F_{net}=23 - 12.74=10.26\space N\). Since \(F_{net}=ma\), then \(a=\frac{F_{net}}{m}\). Substituting \(F_{net}=10.26\space N\) and \(m = 1.3\space kg\), we get \(a=\frac{10.26}{1.3}\)

Step3: Calculate the value of acceleration

\(a=\frac{10.26}{1.3}=7.8923\approx7.9\space m/s^{2}\)

Answer:

\(7.9\space m/s^{2}\)