Question

question 10 of 29
determine the chemical symbols for the neutral elements corresponding to their electronic configurations.
use proper formatting; letter case matters!
$1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6$ :
$1s^2 2s^2 2p^3$ :
$1s^2 2s^2 2p^6 3s^2 3p^6$ :
$1s^2 2s^2 2p^6 3s^2 3p^3$ :

Explanation:

Step1: Calculate total electrons for first configuration

For \(1s^22s^22p^63s^23p^63d^{10}4s^24p^6\), sum exponents: \(2 + 2+6 + 2+6 + 10+2 + 6=36\). Atomic number 36 is Kr (Krypton).

Step2: Calculate total electrons for second configuration

For \(1s^22s^22p^3\), sum exponents: \(2 + 2+3 = 7\). Atomic number 7 is N (Nitrogen).

Step3: Calculate total electrons for third configuration

For \(1s^22s^22p^63s^23p^6\), sum exponents: \(2 + 2+6 + 2+6 = 18\). Atomic number 18 is Ar (Argon).

Step4: Calculate total electrons for fourth configuration

For \(1s^22s^22p^63s^23p^3\), sum exponents: \(2 + 2+6 + 2+3 = 15\). Atomic number 15 is P (Phosphorus).

Answer:

First: Kr
Second: N
Third: Ar
Fourth: P