Question

question 2 (03.05 mc) (multiple choice worth 1 point) which set of transformations would prove \\( \triangle l m n \sim \triangle p q r \\)? dilate \\( \triangle p q r \\) by the scale factor of 2 from point \\( r \\), and translate \\( \triangle p^{\prime} q^{\prime} r^{\prime} \\) by the rule \\( (x+0, y-1) \\). dilate \\( \triangle p q r \\) by the scale factor of 2 from point \\( q \\), and translate \\( \triangle p^{\prime} q^{\prime} r^{\prime} \\) by the rule \\( (x+1, y+0) \\). translate \\( \triangle p q r \\) by the rule \\( (x+1, y+1) \\), and dilate \\( \triangle p^{\prime} q^{\prime} r^{\prime} \\) by a scale factor of 2 from point \\( p \\). translate \\( \triangle p q r \\) by the rule \\( (x+1, y-1) \\), and dilate \\( \triangle p^{\prime} q^{\prime} r^{\prime} \\) by a scale factor of 2 from point \\( r \\).

Explanation:

Step 1: Analizar la dilatación

Para probar que \(\triangle LMN\sim\triangle PQR\), primero se debe dilatar \(\triangle PQR\) por un factor de escala. Observando las coordenadas, se ve que \(R\) es un vértice común en la dilatación.

Step 2: Analizar la traslación

Después de la dilatación, se debe trasladar el triángulo dilatado. La regla \((x + 0,y - 1)\) es adecuada para alinear los triángulos.

Answer:

Dilate \(\triangle PQR\) by the scale factor of \(2\) from point \(R\), and translate \(\triangle P'Q'R'\) by the rule \((x + 0,y - 1)\).