Question

quadrilateral abcd is drawn in coordinate plane. it will be reflected across y - axis to produce image abcd. what would be the location of abcd? a. quadrant 1 b. quadrant 2 c. quadrant 3 d. quadrant 4

Explanation:

Step1: Recall the rule of reflection across y - axis

When a point \((x,y)\) is reflected across the \(y -\)axis, the transformation rule is \((x,y)\to(-x,y)\).

Step2: Analyze the quadrant of the original quadrilateral

Quadrilateral \(ABCD\) is in Quadrant \(3\). In Quadrant \(3\), \(x<0\) and \(y < 0\). After reflection across the \(y -\)axis, for a point \((x,y)\) on \(ABCD\) (where \(x<0,y < 0\)), the image point \((-x,y)\) will have \(-x>0\) and \(y < 0\).

Step3: Determine the quadrant of the image

Points with \(x>0\) and \(y < 0\) lie in Quadrant \(4\).

Answer:

D. Quadrant 4