Question

a quadratic equation of the form $0 = ax^2 + bx + c$ has a discriminant value of -16. how many real number solutions does the equation have?

• -1
• 0
• 1
• 2

Explanation:

Step1: Recall discriminant rules

For quadratic \(ax^2 + bx + c = 0\), discriminant \(D = b^2 - 4ac\). Solutions:

• \(D > 0\): 2 real solutions.
• \(D = 0\): 1 real solution.
• \(D < 0\): 0 real solutions (complex).

Step2: Analyze given discriminant

Given \(D = -16\), which is \(< 0\). So no real solutions.

Answer:

0 (corresponding to the option with 0)