Question

q4 a 2kg ball is dropped from a height of 10m
a. find the potential energy at the top.
b. find its kinetic energy just before hitting the ground
q5 in no less than one paragraph summarize your understanding of work, energy and energy transformation.

Explanation:

Step1: Calculate potential energy

The formula for gravitational potential energy is \(U = mgh\), where \(m = 2\space kg\), \(g= 9.8\space m/s^{2}\), \(h = 10\space m\).

$$U=2\times9.8\times10$$

Step2: Calculate kinetic energy

Using the conservation of mechanical energy (assuming no air - resistance), the potential energy at the top is converted into kinetic energy just before hitting the ground. So \(K = U\).

Answer:

a. The potential energy at the top is \(U = 196\space J\).
b. The kinetic energy just before hitting the ground is \(K=196\space J\).