Question

q28. (2 points) show calculation for the number of fluoride ions (f-) in 3.60 moles of alf3 (aluminum fluoride) formula units;

Explanation:

Step1: Determine the number of fluoride ions per formula unit

In \(AlF_3\), there are 3 \(F^-\) ions per formula unit.

Step2: Calculate the number of moles of fluoride ions

If there are 3.60 moles of \(AlF_3\), then the number of moles of \(F^-\) ions is \(n = 3.60\times3= 10.8\) moles.

Step3: Use Avogadro's number (\(N_A=6.022\times 10^{23}\) ions/mol) to find the number of ions

The number of \(F^-\) ions \(N=n\times N_A\). Substitute \(n = 10.8\) moles and \(N_A = 6.022\times 10^{23}\) ions/mol.
\(N=10.8\times6.022\times 10^{23}\)
\(N = 6.50376\times10^{24}\)

Answer:

\(6.50\times 10^{24}\) fluoride ions.