Question

provide the oxidation number of the s atom in so₃²⁻.

Explanation:

Step1: Set up equation

Let the oxidation number of \(S\) be \(x\). The oxidation number of \(O\) is \(- 2\). The overall charge of the ion \(SO_{3}^{2 - }\) is \(-2\).
We use the formula: \(x+3\times(-2)=- 2\)

Step2: Solve the equation

$$
LATEXBLOCK0
$$

Answer:

\(+4\)