Question

1. a projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. the projectile strikes the ground after time t at horizontal distance d from the base of the platform. if we ignore air resistance, meters is the horizontal distance or range if the projectiles time of flight is 2.5 seconds.

Explanation:

Step1: Analyze horizontal motion

In horizontal direction (no acceleration as \(a = 0\) when ignoring air - resistance), the formula for horizontal displacement is \(d=v_{0x}t\). The initial horizontal velocity \(v_{0x}\) is given as \(40\) m/s and the time of flight \(t = 2.5\) s.

Step2: Calculate horizontal distance

Substitute the values into the formula \(d=v_{0x}t\). So, \(d=(40\space m/s)\times(2.5\space s)\).

Answer:

\(100\)