Question

the production of water proceeds according to the following equation.
$2h_2(g) + o_2(g) \
ightarrow 2h_2o(g)$
which describes a way to speed up the collisions between hydrogen and oxygen molecules to produce more water?
\bigcirc use a less - intense source of heat on the reactants.
\bigcirc maintain the same temperature of the reactants.
\bigcirc place the reactants in a smaller container.
\bigcirc reduce the concentration of the reactants.

Explanation:

To determine how to speed up collisions between \(H_2\) and \(O_2\) molecules, we analyze factors affecting reaction rate (collision frequency):

• Option 1: Less - intense heat lowers temperature, decreasing molecular speed and collision rate. Eliminate.
• Option 2: Constant temperature means no change in molecular speed or collision rate. Eliminate.
• Option 3: Smaller container increases reactant concentration (molecules per unit volume). More molecules in a smaller space leads to more frequent collisions. Correct.
• Option 4: Reducing concentration decreases the number of molecules per unit volume, lowering collision rate. Eliminate.

Answer:

C. Place the reactants in a smaller container.