Question

problem 8: spiral review
figure qrst is graphed on a coordinate plane.
determine the coordinates of the image qrst after the
figure is reflected across the y - axis.
use the coordinate plane if it helps with your thinking.

Explanation:

Step1: Recall the rule for reflection across the y - axis

When a point \((x,y)\) is reflected across the \(y\) - axis, the rule is \((x,y)\to(-x,y)\).

Step2: Apply the rule to point \(Q(3, - 15)\)

For \(Q(3,-15)\), using the rule \((x,y)\to(-x,y)\), we substitute \(x = 3\) and \(y=-15\). So the image of \(Q\) is \((-3,-15)\).

Step3: Apply the rule to point \(R(-6,12)\)

For \(R(-6,12)\), substitute \(x=-6\) and \(y = 12\) into the rule \((x,y)\to(-x,y)\). We get \((-(-6),12)=(6,12)\).

Step4: Apply the rule to point \(S(0,9)\)

For \(S(0,9)\), substitute \(x = 0\) and \(y=9\) into the rule \((x,y)\to(-x,y)\). Since \(-0 = 0\), the image of \(S\) is \((0,9)\).

Step5: Apply the rule to point \(T(-4,-3)\)

For \(T(-4,-3)\), substitute \(x=-4\) and \(y=-3\) into the rule \((x,y)\to(-x,y)\). We get \((-(-4),-3)=(4,-3)\).

Answer:

Pre - image Coordinates	Image Coordinates
\(R(-6,12)\)	\(R'(6,12)\)
\(S(0,9)\)	\(S'(0,9)\)
\(T(-4,-3)\)	\(T'(4,-3)\)