Question

(c) problem 20: (first taught in lesson 53) in this parallelogram, find x and y. 4y - 13 y + 1 3x - 5 15 - x after you enter your answer press go. x = y =

Explanation:

Step1: Use the property of parallelogram (opposite sides are equal)

For the pair of sides \(3x - 5\) and \(15 - x\):
\(3x-5=15 - x\)
Add \(x\) to both sides: \(3x+x-5=15 - x+x\), \(4x-5 = 15\)
Add \(5\) to both sides: \(4x-5 + 5=15 + 5\), \(4x=20\)
Divide both sides by \(4\): \(x=\frac{20}{4}=5\)

Step2: Use the property of parallelogram (opposite sides are equal) for the other pair of sides

For the pair of sides \(4y-13\) and \(y + 1\):
\(4y-13=y + 1\)
Subtract \(y\) from both sides: \(4y-y-13=y - y+ 1\), \(3y-13 = 1\)
Add \(13\) to both sides: \(3y-13 + 13=1 + 13\), \(3y=14\)
Divide both sides by \(3\): \(y=\frac{14}{3}\)

Answer:

\(x = 5\), \(y=\frac{14}{3}\)