Question

problem 13: find the measures of the angles of an isosceles triangle with a vertex angle of 88°. after you enter your answer press go.

Explanation:

Step1: Recall angle - sum property

The sum of the interior angles of a triangle is $180^{\circ}$. In an isosceles triangle, two base - angles are equal. Let the measure of each base - angle be $x$.

Step2: Set up an equation

We know that the vertex angle is $88^{\circ}$ and the sum of the three angles is $180^{\circ}$. So, $88 + x+x=180$.

Step3: Simplify the equation

Combining like terms, we get $88 + 2x=180$.

Step4: Solve for $x$

Subtract 88 from both sides: $2x=180 - 88=92$. Then divide both sides by 2: $x = 46^{\circ}$.
So the angles of the isosceles triangle are $88^{\circ},46^{\circ},46^{\circ}$.

Answer:

$88^{\circ},46^{\circ},46^{\circ}$