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if the pressure exerted by a gas at 25 degrees c in a volume of 0.044 l…

Question

if the pressure exerted by a gas at 25 degrees c in a volume of 0.044 l is 3.81 atm, how many moles of gas are present?

Explanation:

Step1: Convert temperature to Kelvin

$$T = 25 + 273.15 = 298.15\ K$$

Step2: Use ideal gas law \(PV = nRT\)

We know \(P = 3.81\ atm\), \(V=0.044\ L\), \(R = 0.0821\ L\cdot atm/(mol\cdot K)\)
Rearrange for \(n\): \(n=\frac{PV}{RT}\)
Substitute values:
$$n=\frac{3.81\times0.044}{0.0821\times298.15}$$
$$n=\frac{0.16764}{24.487915}$$
$$n\approx0.0069\ mol$$

Answer:

\(0.0069\ mol\)