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practice it! three people were jogging in the park. each person is repr…

Question

practice it!
three people were jogging in the park. each person is represented as a, b, or c on
the distance-time graph.
select the statement(s) that accurately describe the data shown on the distance-
time graph.
person a traveled at a constant speed of 10 meters per second.
each person traveled at a constant speed.
person c traveled at a constant speed of 3 meters per second.
person b traveled at a slower speed than person a.
person b traveled the greatest distance.
graph: distance (m) vs time (s), y-axis 0–40, x-axis 0–6, with lines a, b, c, and a horizontal red line

Explanation:

Response

To solve this, we analyze each statement using the distance - time graph (where speed = $\frac{\text{distance}}{\text{time}}$ for constant - speed motion, and a straight - line graph indicates constant speed):

Statement 1: Person A traveled at a constant speed of 10 meters per second.
  • For Person A, at $t = 4$ seconds, the distance $d=40$ meters. Using the speed formula $v=\frac{d}{t}$, we get $v=\frac{40}{4}=10$ m/s. Also, the graph of Person A is a straight line, so the speed is constant. So this statement is correct.
Statement 2: Each person traveled at a constant speed.
  • The graphs of A, B, and C are straight lines (Person C's graph is also a straight line, and Person B's graph is a straight line). A straight - line distance - time graph implies that the speed (slope of the line) is constant. So each person has a constant speed. This statement is correct.
Statement 3: Person C traveled at a constant speed of 3 meters per second.
  • For Person C, at $t = 6$ seconds, the distance $d = 20$ meters. Using the speed formula $v=\frac{d}{t}$, we get $v=\frac{20}{6}\approx3.33$ m/s, not 3 m/s. So this statement is incorrect.
Statement 4: Person B traveled at a slower speed than Person A.
  • For Person A, $v_A=\frac{40}{4} = 10$ m/s. For Person B, at $t = 6$ seconds, $d = 38$ meters (approx, from the graph). $v_B=\frac{38}{6}\approx6.33$ m/s. Since $6.33\lt10$, Person B's speed is slower than Person A's speed. This statement is correct.
Statement 5: Person B traveled the greatest distance.
  • At $t = 6$ seconds, Person A would travel $d_A=10\times6 = 60$ meters (extrapolating from the speed), Person B would travel around 38 meters, and Person C would travel around 20 meters. So Person A travels the greatest distance, not Person B. This statement is incorrect.

Answer:

  • Person A traveled at a constant speed of 10 meters per second. (Correct)
  • Each person traveled at a constant speed. (Correct)
  • Person B traveled at a slower speed than Person A. (Correct)