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Question
1 - 4 practice problems
solve each of the following problems as directed. show all your work. use the correct abbreviation for each unit.
- convert 83 cm into meters.
- convert 459 l into milliliters.
- express 1123 pg in nanograms.
- express 0.032 m³ in liters.
- express 2.5 mm in micrometers.
- which is the longer amount of time, 1351 ps or 1.2 ns?
- which is the larger pressure, 232.1 kpa or 125,487 pa?
- which is the smaller mass, 285.0 cg or 23.78 dg?
- which is the shorter length, 175.6 mm or 38.4 cm?
- convert the following masses into grams.
a. 0.7824 mg
b. 345,000 ng
c. 0.00378 kg
d. 34,981 μg
Step1: Recall conversion factor for length
$1\ m = 100\ cm$, so to convert $83\ cm$ to $m$, divide by 100.
$83\div100 = 0.83\ m$
Step2: Recall conversion factor for volume
$1\ L=1000\ mL$, so to convert $459\ L$ to $mL$, multiply by 1000.
$459\times1000 = 459000\ mL$
Step3: Recall conversion factor for mass (mass - mass unit)
$1\ ng = 1000\ pg$, so to convert $1123\ pg$ to $ng$, divide by 1000.
$1123\div1000 = 1.123\ ng$
Step4: Recall conversion factor for volume (volume - volume unit)
$1\ m^{3}=1000\ L$, so to convert $0.032\ m^{3}$ to $L$, multiply by 1000.
$0.032\times1000 = 32\ L$
Step5: Recall conversion factor for length
$1\ mm = 1000\ \mu m$, so to convert $2.5\ mm$ to $\mu m$, multiply by 1000.
$2.5\times1000 = 2500\ \mu m$
Step6: Recall conversion factor for time
$1\ ns = 1000\ ps$, so $1.2\ ns=1.2\times1000 = 1200\ ps$. Since $1351\ ps>1200\ ps$, $1351\ ps$ is longer.
Step7: Recall conversion factor for pressure
$1\ kPa = 1000\ Pa$, so $232.1\ kPa=232.1\times1000 = 232100\ Pa$. Since $232100\ Pa>125487\ Pa$, $232.1\ kPa$ is larger.
Step8: Recall conversion factor for mass
$1\ cg = 0.01\ g$ and $1\ dg = 0.1\ g$. So $285.0\ cg=285.0\times0.01 = 2.85\ g$ and $23.78\ dg=23.78\times0.1 = 2.378\ g$. So $23.78\ dg$ is smaller.
Step9: Recall conversion factor for length
$1\ cm = 10\ mm$, so $38.4\ cm = 38.4\times10=384\ mm$. Since $175.6\ mm<384\ mm$, $175.6\ mm$ is shorter.
Step10a: Recall conversion factor for mass
$1\ mg = 0.001\ g$, so $0.7824\ mg=0.7824\times0.001 = 0.0007824\ g$
Step10b: Recall conversion factor for mass
$1\ ng = 1\times10^{-9}\ g$, so $345000\ ng=345000\times1\times10^{-9}=0.000345\ g$
Step10c: Recall conversion factor for mass
$1\ kg = 1000\ g$, so $0.00378\ kg=0.00378\times1000 = 3.78\ g$
Step10d: Recall conversion factor for mass
$1\ \mu g = 1\times10^{- 6}\ g$, so $34981\ \mu g=34981\times1\times10^{-6}=0.034981\ g$
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- $0.83\ m$
- $459000\ mL$
- $1.123\ ng$
- $32\ L$
- $2500\ \mu m$
- $1351\ ps$
- $232.1\ kPa$
- $23.78\ dg$
- $175.6\ mm$
10a. $0.0007824\ g$
10b. $0.000345\ g$
10c. $3.78\ g$
10d. $0.034981\ g$