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Question
practice d: (first taught in lesson 16) two angles are supplementary. the measure of one angle is 6 less than 20% of the other. find the measures of both angles. after you enter your answer press go. and
Step1: Set up variables
Let one angle be \(x\). Then the other angle is \(0.2x - 6\).
Step2: Use the supplementary - angle property
Since supplementary angles sum to \(180^{\circ}\), we have the equation \(x+(0.2x - 6)=180\).
Simplify the left - hand side: \(x + 0.2x-6=1.2x - 6\).
So, \(1.2x-6 = 180\).
Add \(6\) to both sides: \(1.2x=180 + 6=186\).
Divide both sides by \(1.2\): \(x=\frac{186}{1.2}=155\).
Step3: Find the second angle
Substitute \(x = 155\) into \(0.2x-6\).
\(0.2\times155-6=31 - 6=25\).
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\(25\) and \(155\)