Question

power | work and energy | physics | khan academy
by julia efter
power | work and energy | physics | khan academy
khanacaddeemymedicine
3 sec
p =
1 sec
p = 653 j/s
p = 1960 j/s
multiple - choice question
who transferred more energy during weight lifting?
the figure on the left
the figure on the right
rewatch
submit

Explanation:

Step1: Recall the formula for power

Power \( P=\frac{W}{t} \), where \( W \) is work (energy transferred) and \( t \) is time. Rearranging gives \( W = P\times t \).

Step2: Calculate energy for left - figure

For the left - figure, \( P = 653\ J/s \) and \( t = 3\ s \). So \( W_{left}=653\times3=1959\ J \).

Step3: Calculate energy for right - figure

For the right - figure, \( P = 1960\ J/s \) and \( t = 1\ s \). So \( W_{right}=1960\times1 = 1960\ J \).

Answer:

The figure on the RIGHT