Question

1. the position-time graph represents part of a car trip along a straight road. what is the average velocity of the car for the first 6 seconds? 20 m/s, 15 m/s, 8 m/s, 12 m/s

Explanation:

Step1: Recall average velocity formula

Average velocity \( v_{avg} = \frac{\Delta x}{\Delta t} \), where \( \Delta x \) is displacement and \( \Delta t \) is time interval.

Step2: Find displacement at \( t = 6s \)

From the graph, at \( t = 6.0s \), position \( x = 90.0m \) (initial position \( x_0 = 0.0m \) at \( t_0 = 0.0s \)). So \( \Delta x = 90.0 - 0.0 = 90.0m \), \( \Delta t = 6.0 - 0.0 = 6.0s \).

Step3: Calculate average velocity

\( v_{avg} = \frac{90.0}{6.0} = 15m/s \).

Answer:

15 m/s