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1) the polypropylene cubes have a density of 0.946 grams per milliliter…

Question

  1. the polypropylene cubes have a density of 0.946 grams per milliliter. identify the true statement(s).

select all that apply.
a. the cube sinks in 1 - butanol because 1 - butanols density is less than the cubes density.
b. the cube floats on water because the waters density is greater than the cubes density.
c. the cube sinks in 1 - butanol because 1 - butanols density is greater than the cubes density.
d. the cube floats on ethylene glycol because the cubes density is greater than ethylene glycols density.

  1. which liquid(s) could be used for displacement?

select all that apply.
a. ethylene glycol
b. 1 - butanol
c. water

Explanation:

Brief Explanations
  • For question 1:
  • Density comparison principle: If an object's density (\(

ho_{object}\)) is less than the liquid's density (\(
ho_{liquid}\)), it floats (\(
ho_{object}<
ho_{liquid}\Rightarrow float\)); if \(
ho_{object}>
ho_{liquid}\), it sinks.

  • Given \(

ho_{cube} = 0.946g/mL\).

  • \(

ho_{1 - butanol}=0.81g/mL\), since \(0.946>0.81\) (\(
ho_{cube}>
ho_{1 - butanol}\)), the cube sinks in 1 - butanol (so option A is correct).

  • \(

ho_{water}=1g/mL\), since \(0.946 < 1\) (\(
ho_{cube}<
ho_{water}\)), the cube floats on water (so option B is correct).

  • \(

ho_{ethylene\ glycol}=1.11g/mL\), since \(0.946<1.11\) (\(
ho_{cube}<
ho_{ethylene\ glycol}\)), the cube floats on ethylene glycol (so option D is correct).

  • For question 2:
  • Displacement principle: A liquid can be used for displacement if the object sinks in it (\(

ho_{object}>
ho_{liquid}\)).

  • Since \(

ho_{cube} = 0.946g/mL\) and \(
ho_{1 - butanol}=0.81g/mL\) (\(
ho_{cube}>
ho_{1 - butanol}\)), 1 - butanol (option B) can be used for displacement.

Answer:

  1. A. The cube sinks in 1 - butanol because 1 - butanol’s density is less than the cube’s density; B. The cube floats on water because the water’s density is greater than the cube’s density; D. The cube floats on ethylene glycol because the cube’s density is greater than ethylene glycol’s density.
  2. B. 1 - Butanol.