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Question
a polynomial is factored using algebra tiles. which polynomial was factored? options: $x^2 - 2x - 8$, $x^2 + 2x - 8$, $x^2 - 2x - 4$, $x^2 + 2x - 4$
Step1: Analyze the algebra tiles for \(x^2\) term
There is 1 \(+x^2\) tile, so the coefficient of \(x^2\) is 1.
Step2: Analyze the algebra tiles for \(x\) terms
There are 2 \(+x\) tiles and 4 \(-x\) tiles. The total for \(x\) terms: \(2x - 4x=- 2x\).
Step3: Analyze the algebra tiles for constant terms
There are 8 \(-\) (constant -1) tiles, so the constant term is \(-8\).
Step4: Form the polynomial
Combining the terms, the polynomial is \(x^2-2x - 8\).
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\(x^2 - 2x - 8\) (the first option)