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Question
the point-slope form of a line that has a slope of \\(\frac{2}{3}\\) and passes through point \\((6, 0)\\) is shown below.
\\y - 0 = \frac{2}{3}(x - 6)\\
what is the equation in slope-intercept form?
\\(y = \frac{2}{3}x - 12\\)
\\(y = \frac{2}{3}x - 6\\)
\\(y = \frac{2}{3}x - 4\\)
\\(y = \frac{2}{3}x - 8\\)
Distribute the slope on the right side
$$
y - 0 = \frac{2}{3}(x - 6)
$$
$$
y - 0 = \frac{2}{3}x - \frac{2}{3}(6)
$$
Simplify the constant term
$$
\frac{2}{3}(6) = 4
$$
$$
y = \frac{2}{3}x - 4
$$
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- (A) \(y = \frac{2}{3}x - 12\)
- (B) \(y = \frac{2}{3}x - 6\)
- (C) \(y = \frac{2}{3}x - 4\) (Correct answer)
- (D) \(y = \frac{2}{3}x - 8\)