a planet with a mass of 6.2 x 10^6 kg is orbiting a star with a mass of 6.0 x 10^12 kg. the distance from their centers is 7.9 x 10^6 m. what is the gravitational force between them?

Question

Accepted Answer

# Explanation:
## Step1: Recall the formula for gravitational force
The formula for gravitational force is $F = G\frac{m_1m_2}{r^2}$, where $G = 6.67\times10^{- 11}\space Nm^{2}/kg^{2}$, $m_1$ and $m_2$ are the masses of the two objects, and $r$ is the distance between their centers.
## Step2: Substitute the given values into the formula
Given $m_1=6.2\times 10^{8}\space kg$, $m_2 = 6.0\times10^{12}\space kg$, $r = 7.9\times10^{6}\space m$ and $G=6.67\times 10^{-11}\space Nm^{2}/kg^{2}$

$$
\begin{align*}
F&=(6.67\times 10^{-11})\frac{(6.2\times 10^{8})(6.0\times 10^{12})}{(7.9\times 10^{6})^{2}}\
&=(6.67\times 10^{-11})\frac{37.2\times10^{20}}{62.41\times10^{12}}\
&=(6.67\times 10^{-11})\frac{3.72\times10^{21}}{6.241\times10^{13}}\
&=(6.67\times 10^{-11})\times(5.96\times10^{7})\
\end{align*}
$$

## Step3: Calculate the value of $F$
$$
\begin{align*}
F&=(6.67\times5.96)\times10^{-11 + 7}\
&=39.75\times10^{-4}\
&=3.975\times10^{-3}\space N
\end{align*}
$$

# Answer:
$3.975\times 10^{-3}\space N$

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QUESTION IMAGE

Question

Explanation:

Step1: Recall the formula for gravitational force

Step2: Substitute the given values into the formula

Step3: Calculate the value of \(F\)

Answer: