Question

physics a circuit has amperage of 0.01 milliamp. a multimeter measures the amperage of the circuit at 0.06 milliamp. what is the approximate error? milliamp

Explanation:

Step1: Identify true and measured values

True value ($V_{true}$) = 0.01 milliamp, Measured value ($V_{measured}$) = 0.06 milliamp.

Step2: Calculate absolute error

Absolute Error = $|V_{measured} - V_{true}|$ = $|0.06 - 0.01|$ = 0.05 milliamp.

Step3: Calculate relative error (optional, but if approximate error is relative, though here likely absolute or maybe percentage? Wait, the problem says "approximate error"—maybe absolute or percentage. Wait, let's check:

Wait, maybe the question is about percentage error? Let's recalculate.

Percentage Error = $\frac{|V_{measured} - V_{true}|}{V_{true}} \times 100\%$ = $\frac{0.05}{0.01} \times 100\%$ = 500%. But maybe absolute error? Wait, the original true value is 0.01, measured is 0.06. The difference is 0.05. But maybe the question has a typo? Wait, maybe the true value is 0.06 and measured is 0.01? No, the problem says "a circuit has amperage of 0.01 milliamp. A multimeter measures... at 0.06 milliamp." So true is 0.01, measured 0.06.

Wait, maybe the question is asking for absolute error: 0.06 - 0.01 = 0.05 milliamp. Or percentage error: (0.05/0.01)*100 = 500%. But let's see the problem again. The box is labeled "milliamp". So maybe absolute error is 0.05 milliamp.

Answer:

0.05 milliamp (or 500% if percentage error, but based on the box, absolute error is 0.05)