Question

a 4 in. by 5 in. photo is enlarged so that its width (shorter dimension) is 5 in. what is the length of the enlarged photo?

6 in.

5.25 in.

6.25 in.

7 in.

Explanation:

Step1: Set up proportion

Let \( x \) be the length of the enlarged photo. The ratio of width to length should be constant. So, \(\frac{4}{5}=\frac{5}{x}\)

Step2: Cross - multiply

Cross - multiplying gives \( 4x = 5\times5 \), which simplifies to \( 4x=25 \)

Step3: Solve for \( x \)

Divide both sides by 4: \( x=\frac{25}{4}=6.25 \)

Answer:

6.25 in.