QUESTION IMAGE
Question
part i - covalent only
chemical nomenclature
write the formulas:
- dihydrogen monoxide
- tetrasulfur trichloride
- triphosphorus octoxide
- pentaphosphorus hexoxide
- heptacarbon dichloride
- decanitrogen octoxide
- diphosphorus nonanitride
- diarsenic pentoxide
- sulfur dioxide
- nitrogen trioxide
Step1: Determine prefix - element relationship
In covalent compound nomenclature, prefixes (di - 2, mono - 1, tetra - 4, tri - 3, octa - 8, penta - 5, hepta - 7, deca - 10, nona - 9) are used to denote the number of atoms of each element.
For example, for "dihydrogen monoxide":
- "di -" (prefix for hydrogen) means 2 hydrogen atoms ($H$).
- "mono -" (prefix for oxygen) means 1 oxygen atom ($O$). So the formula is $H_{2}O$.
Step2: Apply the rule to each compound
- For "tetrasulfur trichloride":
- "tetra -" (sulfur) $\to4$ $S$ atoms.
- "tri -" (chloride) $\to3$ $Cl$ atoms. Formula: $S_{4}Cl_{3}$.
- For "triphosphorus octoxide":
- "tri -" (phosphorus) $\to3$ $P$ atoms.
- "octa -" (oxide) $\to8$ $O$ atoms. Formula: $P_{3}O_{8}$.
- For "pentaphosphorus hexoxide":
- "penta -" (phosphorus) $\to5$ $P$ atoms.
- "hexa -" (oxide) $\to6$ $O$ atoms. Formula: $P_{5}O_{6}$.
- For "heptacarbon dichloride":
- "hepta -" (carbon) $\to7$ $C$ atoms.
- "di -" (chloride) $\to2$ $Cl$ atoms. Formula: $C_{7}Cl_{2}$.
- For "decanitrogen octoxide":
- "deca -" (nitrogen) $\to10$ $N$ atoms.
- "octa -" (oxide) $\to8$ $O$ atoms. Formula: $N_{10}O_{8}$.
- For "diphosphorus nonanitride":
- "di -" (phosphorus) $\to2$ $P$ atoms.
- "nona -" (nitride) $\to9$ $N$ atoms. Formula: $P_{2}N_{9}$.
- For "diarsenic pentoxide":
- "di -" (arsenic) $\to2$ $As$ atoms.
- "penta -" (oxide) $\to5$ $O$ atoms. Formula: $As_{2}O_{5}$.
- For "sulfur dioxide":
- No prefix for sulfur (implies 1 $S$ atom).
- "di -" (oxide) $\to2$ $O$ atoms. Formula: $SO_{2}$.
- For "nitrogen trioxide":
- No prefix for nitrogen (implies 1 $N$ atom).
- "tri -" (oxide) $\to3$ $O$ atoms. Formula: $NO_{3}$.
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- $H_{2}O$
- $S_{4}Cl_{3}$
- $P_{3}O_{8}$
- $P_{5}O_{6}$
- $C_{7}Cl_{2}$
- $N_{10}O_{8}$
- $P_{2}N_{9}$
- $As_{2}O_{5}$
- $SO_{2}$
- $NO_{3}$