QUESTION IMAGE
Question
parallelogram fghj was dilated and translated to form similar parallelogram fghj. what is the scale factor of the dilation? \\(\frac{1}{8}\\) \\(\frac{1}{4}\\) 8 4
Step1: Find length of FG (original)
From graph, FG spans 2 units (e.g., from x=-4 to x=-2? Wait, no, original FG: F at (-5,5), G at (-3,5)? Wait, better: count grid. Original parallelogram FGHJ: FG is horizontal? Wait, original F, G, H, J: Let's take FG length. From F to G: x-coordinates, say F is (-5,5), G is (-3,5)? No, looking at grid, original FGHJ: FG is 2 units (horizontal). Then F'G' length: F' is (-6,1), G' is (4,1)? Wait, no, F' to G': from x=-6 to x=4? Wait, no, the lower parallelogram F'G'H'J': F' is at (-6,1), G' at (4,1)? Wait, no, looking at the grid, F' is at (-6,1), G' at (4,1)? Wait, no, the x-axis: F' is at x=-6, G' at x=4? Wait, no, the grid lines: F' is at (-6,1), G' at (4,1)? Wait, no, the original FGHJ: let's take FG length. Original F is at (-5,5), G at (-3,5): so length FG is 2 units (from x=-5 to x=-3, difference 2). Then F'G': F' is at (-6,1), G' at (4,1): length is 10? Wait, no, maybe I messed up. Wait, the lower parallelogram: F' is at (-6,1), G' at (4,1)? No, looking at the graph, F' is at (-6,1), G' at (4,1)? Wait, no, the x-axis: F' is at x=-6, G' at x=4? Wait, the distance between F' and G' is 4 - (-6) = 10? No, that can't be. Wait, maybe original FG is 2 units, and F'G' is 8 units? Wait, no, let's check the y-coordinate. Wait, original parallelogram FGHJ: height (vertical) is 2 units (from y=2 to y=5? No, original F is at (-5,5), J at (-5,3), so height is 2. Then F'G'H'J': height is from y=1 to y=-5? Wait, no, the lower parallelogram: F' is at (-6,1), J' at (-6,-5), so height is 6? Wait, no, maybe I should take horizontal length. Original FG: length 2 (from x=-5 to x=-3). F'G': length 8 (from x=-6 to x=2? Wait, no, F' is at (-6,1), G' at (2,1)? Wait, the grid: each square is 1 unit. So original FG: from F (-5,5) to G (-3,5): length 2. F'G': from F' (-6,1) to G' (2,1): length 8? Wait, no, -6 to 2 is 8 units? Wait, -6 to 2 is 8? 2 - (-6) = 8. So original length FG = 2, new length F'G' = 8? Wait, no, that would be scale factor 4. Wait, original FG: 2 units, F'G' = 8 units? Wait, 8 / 2 = 4? Wait, no, maybe original FG is 2, F'G' is 8? Wait, no, let's check again. Original FGHJ: F is at (-5,5), G at (-3,5), H at (-2,3), J at (-4,3). So FG length: distance between (-5,5) and (-3,5) is 2. F'G'H'J': F' is at (-6,1), G' at (2,1), H' at (3,-5), J' at (-5,-5). So F'G' length: distance between (-6,1) and (2,1) is 8. So scale factor is new length / original length = 8 / 2 = 4? Wait, no, wait: dilation scale factor is new / original. Wait, but the original is smaller, the image is larger. So original length 2, new length 8: scale factor 4. Wait, but the options are 1/8, 1/4, 8, 4. Wait, maybe I got original and image reversed. Wait, the problem says: Parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'. So FGHJ is original, F'G'H'J' is image. So scale factor is image length / original length. Original FG: 2, image F'G': 8? Wait, no, maybe original FG is 2, image F'G' is 8? Then 8/2=4. So scale factor is 4.
Step2: Confirm with height. Original height: from y=3 to y=5, so 2 units. Image height: from y=-5 to y=1, so 6? Wait, no, original height: F is (x,5), J is (x,3), so height 2. Image F' is (x,1), J' is (x,-5), so height 6? Wait, no, that doesn't match. Wait, maybe I misread the coordinates. Let's look again. Original FGHJ: F is at (-5,5), G at (-3,5), H at (-2,3), J at (-4,3). So FG is horizontal, length 2 (from x=-5 to x=-3). F'G'H'J': F' is at (-6,1), G' at (4,1), H' at (5,-5), J' at (-5,-5). So F'G' length: from x=-6 to x=4, that's 10? No, -6 to 4 is 10. Original FG is 2, 1…
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