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parabolas find the focus and directrix of the following parabola: \\(y …

Question

parabolas

find the focus and directrix of the following parabola:

\\(y - 4)^2 = 16(x - 6)\\

focus: \\((?, \quad)\\)

directrix: \\(x = \quad\\)

Explanation:

Identify vertex and focal parameter

$$ LATEXBLOCK0 $$

Calculate the focus

$$ LATEXBLOCK1 $$

Calculate the directrix

$$ LATEXBLOCK2 $$

Answer:

Find the focus and directrix of the following parabola:

$$(y - 4)^2 = 16(x - 6)$$

Focus: (<blank>10</blank>, <blank>4</blank>)
Directrix: \(x =\) <blank>2</blank>