Question

oxygen has __ valence electrons, therefore it always forms __ bonds.
○ a 2 valence electrons, 6 bonds
○ b 8 valence electrons, 0 bonds
○ c 2 valence electrons, 2 bonds
○ d 6 valence electrons, 2 bonds
question 34 (2 points)
name the following ionic compound: becl2
○ a beryllium chlorine
○ b beryllium ii chloride
○ c beryllium dichloride
○ d beryllium chloride
question 35 (2 points)
what is the formula for sodium nitrate?
○ a nano3
○ b nan
○ c nano2
○ d

Explanation:

• Question 34:
• For ionic compounds, the naming rule is to name the cation first (beryllium) and then the anion. The anion is named by taking the root of the non - metal (chlor -) and adding “-ide”. Since beryllium has a fixed charge of \(+ 2\) and chlorine has a charge of \(-1\), we don't need prefixes (prefixes are for covalent compounds). So it's beryllium chloride.
• Question 35:
• Sodium has a charge of \(+1\) (\(Na^{+}\)). Nitrate is a polyatomic ion with the formula \(NO_{3}^{-}\). Using the criss - cross method (the magnitude of the charge of one ion becomes the subscript of the other), we get \(NaNO_{3}\).

Answer:

• Question 34: d. beryllium chloride
• Question 35: a. \(NaNO_{3}\)