QUESTION IMAGE
Question
opposite directions
- what is the net force on the car?
a. net force =
b. is this force balanced or unbalanced?
- a boy takes his dog for a walk. the dog is pulling with a force of 30n to the right and the boy is pulling backwards with a force of 18n. what is the net force on them?
a. net force =
b. is this force balanced of unbalanced?
- both of the people on the left are pulling with a force of 55n to the left. on the right side of the rope, one person is pulling with 35n to the right, and the other person is pulling 20n to the right. what is the net force on the rope?
a. net force=
b. is this balanced of unbalanced?
- what is the net force of the figure below?
same direction
- look at the picture to the right. both men are pushing on the refrigerator with a force of 100n. what is the net force of the refrigerator?
a. net force=
b. is this force balanc
Step1: Determine net force formula
When forces act in opposite directions, net force \(F_{net}=|F_1 - F_2|\). When forces act in same direction \(F_{net}=F_1 + F_2\). Balanced force: \(F_{net}=0\), Un - balanced force: \(F_{net}
eq0\)
Step2: Solve problem 11
a. Forces on car: \(F_1 = 10N\) (right), \(F_2=7N\) (left). \(F_{net}=|10 - 7|=3N\) (right)
b. Since \(F_{net}=3N
eq0\), un - balanced
Step3: Solve problem 12
a. Dog: \(F_1 = 30N\) (right), Boy: \(F_2 = 18N\) (left). \(F_{net}=|30 - 18|=12N\) (right)
b. \(F_{net}=12N
eq0\), un - balanced
Step4: Solve problem 13
a. Left: \(F_{left}=55N\), Right: \(F_{right}=35 + 20=55N\). \(F_{net}=|55 - 55|=0N\)
b. \(F_{net}=0N\), balanced
Step5: Solve problem 14
a. Right: \(F_{right}=5 + 2=7N\), Left: \(F_{left}=10N\). \(F_{net}=|10 - 7|=3N\) (left)
b. \(F_{net}=3N
eq0\), un - balanced
Step6: Solve problem 15
a. Both men: \(F_1 = F_2 = 100N\) (same direction). \(F_{net}=100+100 = 200N\)
b. \(F_{net}=200N
eq0\), un - balanced
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11.
a. \(3N\) (right)
b. Un - balanced
12.
a. \(12N\) (right)
b. Un - balanced
13.
a. \(0N\)
b. Balanced
14.
a. \(3N\) (left)
b. Un - balanced
15.
a. \(200N\)
b. Un - balanced