Question

one way to determine whether a nu table.
complete the factor table and the ser
factor pairs of 17
1 17
2 not a factor
3 not a factor
4 4
5 not a factor
the number 17 has factors.
the number 17 is a number

Explanation:

Step1: Determine factors of 17

A factor of a number divides it without leaving a remainder. We check numbers: \(17\div1 = 17\) (remainder 0), \(17\div2 = 8.5\) (not integer), \(17\div3\approx5.67\) (not integer), \(17\div4 = 4.25\) (not integer), \(17\div5 = 3.4\) (not integer), and \(17\div17 = 1\) (remainder 0). So the only factors of 17 are 1 and 17.

Step2: Count the factors

From the factor pairs, we have two factors: 1 and 17. For the row with 4, since \(17\div4\) is not an integer, 4 is not a factor, so we should mark "not a factor" there. Then, the number of factors of 17 is 2.

Answer:

For the "4" row: not a factor
The number 17 has 2 factors.
(And 17 is a prime number, as it has only two distinct positive factors: 1 and itself.)