Question

one of these representations is not like the others. tap on the one that doesnt belong.
arrows represent acceleration vectors
arrows represent force vectors
the objects horizontal velocity is constant; its vertical velocity is changing.

Explanation:

Step1: Analyze projectile motion

In projectile motion, the horizontal acceleration \(a_x = 0\) (assuming no air - resistance), so the horizontal force \(F_x=ma_x = 0\). The vertical acceleration \(a_y=-g=- 9.8\ m/s^{2}\) (downward), and the vertical force \(F_y = ma_y\).

Step2: Check each representation

• For the table: \(v_x\) is constant (\(a_x = 0\)), \(v_y\) changes (\(a_y=-9.8\ m/s^{2}\)) which is consistent with projectile motion.
• For the text: “The object’s horizontal velocity is constant; it’s vertical velocity is changing” is also consistent with projectile motion (\(a_x = 0,a_y=-g\)).
• For the right - hand graph (force vectors): In projectile motion, the only force is the gravitational force (vertical). So there should be no horizontal force vectors. But in the left - hand graph (acceleration vectors), if we consider \(a_x = 0\) (no horizontal acceleration vector) and \(a_y=-g\) (vertical acceleration vector), it is correct. However, if we assume the left - hand graph (the one in the red box) is wrong: In projectile motion, the horizontal acceleration is zero. But if the left - hand graph (assuming it's mis - represented) might be thought of as having an error. Wait, no, re - check. Wait, actually, in projectile motion, the acceleration is \(a=-g\hat{j}\) (vertical). The right - hand graph (force vectors) has horizontal force vectors which is wrong (because \(F_x = 0\) in projectile motion, only \(F_y=-mg\)).

Answer:

The graph with force vectors (the one on the right among the two graphs) doesn't belong.