Question

one of these representations is not like the others. tap on the one that doesnt belong. \the objects vertical acceleration changes by -9.8 m/s every second.\ \the objects horizontal velocity is constant; its vertical velocity is changing.\

Explanation:

Step1: Analyze the table

The table shows that the horizontal velocity \(v_x = 16.0\ m/s\) (constant) and the vertical velocity \(v_y\) changes. The change in vertical velocity per second \(\Delta v_y=-9.8\ m/s\) (since \(v_y(1)-v_y(0)=-9.8 - 0=-9.8\), \(v_y(2)-v_y(1)=-19.6-(-9.8)=-9.8\) etc.). So the vertical acceleration \(a_y=\frac{\Delta v_y}{\Delta t}=-9.8\ m/s^2\) (constant).

Step2: Analyze the second statement

The second statement “The object’s vertical acceleration changes by \(- 9.8\ m/s\) every second” is wrong. Acceleration is the rate of change of velocity. Here \(a_y=\frac{\Delta v_y}{\Delta t}=-9.8\ m/s^2\) (constant), not that acceleration changes.

Step3: Analyze the third statement

The third statement “The object’s horizontal velocity is constant; it’s vertical velocity is changing” is correct as seen from the table (\(v_x = 16.0\ m/s\) constant and \(v_y\) changing).

Step4: Analyze the vector diagram

The vector diagram (arrows represent velocity vectors) shows horizontal velocity (constant - same length horizontal arrows) and vertical velocity changing (increasing length of vertical arrows as \(|v_y|\) increases with time) which is consistent with projectile - like motion (constant horizontal velocity and constant vertical acceleration \(a = g=- 9.8\ m/s^2\)).

Answer:

The statement “The object’s vertical acceleration changes by \(-9.8\ m/s\) every second”