Question

one atom of sodium (na) has a mass of 23 amu (atomic mass units). according to the law of conservation of mass, if two atoms of sodium are present in the reactants of a chemical equation, how much will the sodium weigh in the products of the reaction? (1 point)
23 amu
11.5 amu
46 amu
184 amu

Explanation:

Step1: Recall Law of Conservation of Mass

The Law of Conservation of Mass states that mass is conserved in a chemical reaction, meaning the total mass of reactants equals the total mass of products. For sodium atoms, each has a mass of 23 amu.

Step2: Calculate mass of two sodium atoms

If one Na atom is 23 amu, then two Na atoms will have a mass of \(2\times23 = 46\) amu. By the Law of Conservation of Mass, the mass of sodium in products will equal its mass in reactants.

Answer:

46 amu (the option with "46 amu")