Question

olve the following equations

1. $4(x + 5) - 6 = 2$

a. $x = 3$
b. $x = 7$
c. $x = -3$
d. $x = -2$

1. $\frac{x}{3} - 6 = -1$

a. $x = 2$
b. $x = 15$
c. $x = -3$

Explanation:

Step1: Solve \(4(x + 5)-6 = 2\)

First, add 6 to both sides: \(4(x + 5)-6 + 6=2 + 6\), so \(4(x + 5)=8\). Then divide both sides by 4: \(\frac{4(x + 5)}{4}=\frac{8}{4}\), which gives \(x + 5 = 2\). Subtract 5 from both sides: \(x=2 - 5=-3\).

Step2: Solve \(\frac{x}{3}-6=-1\)

Add 6 to both sides: \(\frac{x}{3}-6 + 6=-1 + 6\), so \(\frac{x}{3}=5\). Multiply both sides by 3: \(x = 5\times3 = 15\).

Answer:

1. c. \(x=-3\)
2. b. \(x = 15\)