Question

off the edge of a table that has a height of 1.00 meter. the 27 seconds to hit the ground 0.65 meters from the base of the t was the horizontal velocity of the ball as it rolled off the table? 0.18 m/s 2.4 m/s 3.7 m/s 4.9 m/s

Explanation:

Step1: Analyze horizontal motion

In horizontal direction, there is no acceleration ($a = 0$). The formula for horizontal motion is $x=v_{0x}t$, where $x$ is the horizontal distance, $v_{0x}$ is the initial horizontal velocity, and $t$ is the time of flight. We need to solve for $v_{0x}$, so $v_{0x}=\frac{x}{t}$.

Step2: Substitute values

Given $x = 0.65$ m and $t=0.27$ s. Substitute these values into the formula: $v_{0x}=\frac{0.65}{0.27}\approx2.4$ m/s.

Answer:

2.4 m/s