Question

1. an object of mass 5.0 kg is lifted vertically upward by 2.0 m. assuming the acceleration due to gravity is $9.8\\ \mathrm{m/s^2}$, how much work is done against gravity?

a. 10 j
b. 20 j
c. 49 j
d. 98 j

Explanation:

Step1: Recall the formula for work done against gravity

The work done against gravity is equal to the change in gravitational potential energy, and the formula is \( W = mgh \), where \( m \) is the mass, \( g \) is the acceleration due to gravity, and \( h \) is the height lifted.

Step2: Substitute the given values into the formula

Given \( m = 5.0 \, \text{kg} \), \( g = 9.8 \, \text{m/s}^2 \), and \( h = 2.0 \, \text{m} \).
Substitute these values into the formula: \( W = 5.0 \times 9.8 \times 2.0 \)

Step3: Calculate the result

First, calculate \( 5.0 \times 9.8 = 49 \), then multiply by \( 2.0 \): \( 49 \times 2.0 = 98 \, \text{J} \)

Answer:

D. 98 J