Question

an object has a kinetic energy of 25 j and a mass of 34 kg, how fast is the object moving?

Explanation:

Step1: Recall the kinetic energy formula

The formula for kinetic energy is \(KE=\frac{1}{2}mv^{2}\), where \(KE\) is kinetic energy, \(m\) is mass, and \(v\) is velocity. We need to solve for \(v\). Rearranging the formula for \(v\) gives \(v = \sqrt{\frac{2KE}{m}}\).

Step2: Substitute the given values

Given \(KE = 25\space J\) and \(m=34\space kg\). Substitute these into the formula: \(v=\sqrt{\frac{2\times25}{34}}\).
First, calculate the numerator \(2\times25 = 50\). Then we have \(v=\sqrt{\frac{50}{34}}\approx\sqrt{1.4706}\).

Step3: Calculate the square - root

\(\sqrt{1.4706}\approx1.21\space m/s\)

Answer:

The object is moving at approximately \(1.21\space m/s\)