Question

the nucleus shown undergoes beta-minus decay.
\\(\ce{_{53}^{131}i}\\)
how many protons will the nucleus have after it decays?
(1 point)
\\(\bigcirc\\) 54
\\(\bigcirc\\) 132
\\(\bigcirc\\) 52
\\(\bigcirc\\) 130

Explanation:

Step1: Understand beta - minus decay

In beta - minus decay, a neutron in the nucleus is converted into a proton, an electron (beta particle), and an antineutrino. The general equation for beta - minus decay is \(_{Z}^{A}X
ightarrow_{Z + 1}^{A}Y+_{-1}^{0}e+\bar{
u}\)

Step2: Analyze the given nucleus

For the nucleus \(_{53}^{131}I\), the atomic number \(Z = 53\) (which represents the number of protons). After beta - minus decay, the atomic number \(Z\) increases by 1.

Step3: Calculate the number of protons after decay

Since the initial number of protons (atomic number) is \(Z=53\), after beta - minus decay, the number of protons \(Z'=53 + 1=54\)

Answer:

A. 54