QUESTION IMAGE
Question
ns7-80: changing fractions to decimals (continued)
find the decimal value of each fraction to 3 decimal places:
a)
\\3 \overline{)1\boldsymbol{.}000}\\ \\(\frac{1}{3} \approx \underline{\quad}\\)
b)
\\3 \overline{)2\boldsymbol{.}000}\\ \\(\frac{2}{3} \approx \underline{\quad}\\)
c)
\\6 \overline{)1\boldsymbol{.}000}\\ \\(\frac{1}{6} \approx \underline{\quad}\\)
d)
\\6 \overline{)5\boldsymbol{.}000}\\ \\(\frac{5}{6} \approx \underline{\quad}\\)
Part (a): $\boldsymbol{\frac{1}{3}}$ to 3 decimal places
Step1: Divide 1 by 3
We perform the long division of 1 ÷ 3. 3 goes into 1 zero times, so we write 0 and a decimal point. Then we consider 10 (since we add a zero after the decimal). 3 goes into 10 three times (3×3 = 9), with a remainder of 1.
Step2: Continue the division
Bring down another zero, making it 10 again. 3 goes into 10 three times (3×3 = 9), remainder 1. This pattern repeats. To three decimal places, we look at the fourth digit to round. The division gives 0.3333..., so rounding to three decimal places, we take the first three digits after the decimal.
Step1: Divide 2 by 3
Perform long division: 3 goes into 2 zero times, write 0 and decimal. Consider 20. 3 goes into 20 six times (3×6 = 18), remainder 2.
Step2: Continue the division
Bring down a zero, making it 20 again. 3 goes into 20 six times (3×6 = 18), remainder 2. This repeats. The division gives 0.6666..., so to three decimal places, we take the first three digits after the decimal.
Step1: Divide 1 by 6
Perform long division: 6 goes into 1 zero times, write 0 and decimal. Consider 10. 6 goes into 10 once (6×1 = 6), remainder 4.
Step2: Bring down a zero
Now we have 40. 6 goes into 40 six times (6×6 = 36), remainder 4.
Step3: Bring down another zero
Now we have 40 again. 6 goes into 40 six times (6×6 = 36), remainder 4. The division gives 0.1666..., so truncating to three decimal places, we take the first three digits after the decimal.
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$\frac{1}{3} \approx 0.333$