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now, the molar mass of table sugar or sucrose (c₁₂h₂₂o₁₁) is 342.30 gra…

Question

now, the molar mass of table sugar or sucrose (c₁₂h₂₂o₁₁) is 342.30 grams per mole (g / mol). this means that 1 mole of table sugar is equal to 342.30 grams. so how many moles is your sample, which weighed 50.5 grams? report your answer to 3 significant figures.
use the equation you set up below to calculate the number of moles of sucrose in your sample.
units you have conversion factor moles of sucrose
50.5 grams sucrose × 1 mol sucrose / 342.30 grams sucrose =

Explanation:

Step1: Set up the calculation

We use the formula \(n=\frac{m}{M}\), where \(n\) is the number of moles, \(m\) is the mass (\(m = 50.5\space g\)), and \(M\) is the molar mass (\(M=342.30\space g/mol\)).

$$n=\frac{50.5\space g}{342.30\space g/mol}$$

Step2: Perform the division

$$n=\frac{50.5}{342.30}\approx0.1475$$

Step3: Round to 3 significant figures

The fourth digit is \(5\), so we round up the third digit. \(0.1475\approx0.148\)

Answer:

\(0.148\space mol\)