Question

nov 24
app.nearpod.com
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n₂ + h₂ → nh₃

Explanation:

Step1: Write the unbalanced equation

The reaction is \( \text{N}_2 + \text{H}_2
ightarrow \text{NH}_3 \).

Step2: Balance nitrogen atoms

There are 2 N atoms on the left (in \( \text{N}_2 \)) and 1 N atom on the right (in \( \text{NH}_3 \)). So we put a coefficient of 2 in front of \( \text{NH}_3 \) to balance N: \( \text{N}_2 + \text{H}_2
ightarrow 2\text{NH}_3 \).

Step3: Balance hydrogen atoms

Now, on the right, we have \( 2\times3 = 6 \) H atoms (from \( 2\text{NH}_3 \)). On the left, we have 2 H atoms (from \( \text{H}_2 \)). So we put a coefficient of 3 in front of \( \text{H}_2 \) to balance H: \( \text{N}_2 + 3\text{H}_2
ightarrow 2\text{NH}_3 \).

Answer:

The balanced equation is \( \text{N}_2 + 3\text{H}_2
ightarrow 2\text{NH}_3 \), so the coefficients are 1 (for \( \text{N}_2 \)), 3 (for \( \text{H}_2 \)), and 2 (for \( \text{NH}_3 \)).