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Question
is the no molecule paramagnetic or diamagnetic? paramagnetic diamagnetic
Step1: Determine the molecular orbital configuration of NO
Nitrogen has 7 electrons and oxygen has 8 electrons. So, NO has \(7 + 8=15\) electrons. The molecular orbital configuration of NO is \(\sigma_{1s}^{2}\sigma_{1s}^{*2}\sigma_{2s}^{2}\sigma_{2s}^{*2}\sigma_{2p}^{2}\pi_{2p}^{4}\pi_{2p}^{*1}\)
Step2: Check for unpaired electrons
In the molecular orbital configuration of NO, there is one unpaired electron in the \(\pi_{2p}^{*}\) orbital.
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Paramagnetic