Question

2.
\frac{}{\mathrm{pcl}_{5}} \
ightarrow \frac{}{\mathrm{pcl}_{3}}+\frac{}{\mathrm{cl}_{2}}

Explanation:

Step1: Balance the chemical equation

According to the law of conservation of mass, the number of atoms of each element on both sides of the chemical equation should be equal.
For the reaction \(PCl_{5}\to PCl_{3}+Cl_{2}\), we can see that on the left - hand side, we have 1 \(P\) atom and 5 \(Cl\) atoms. On the right - hand side, we have 1 \(P\) atom (\(PCl_{3}\) contributes 1 \(P\) atom) and \(3 + 2=5\) \(Cl\) atoms (\(PCl_{3}\) contributes 3 \(Cl\) atoms and \(Cl_{2}\) contributes 2 \(Cl\) atoms). So the balanced chemical equation is \(2PCl_{5}\to 2PCl_{3}+Cl_{2}\)

Answer:

\(2PCl_{5}\to 2PCl_{3}+Cl_{2}\)