Question

name:jamison m.
electron configurations practice #2
part 1: using your periodic table, identify the eleme
$1s^2 2s^2$
$1s^2 2s^2 2p^5$
$1s^2 2s^2 2p^6 3s^2 3p^2$

Explanation:

Step1: Calculate total electrons for \(1s^2 2s^2\)

Sum the exponents: \(2 + 2 = 4\). Atomic number = 4, element is Beryllium (Be).

Step2: Calculate total electrons for \(1s^2 2s^2 2p^5\)

Sum exponents: \(2 + 2 + 5 = 9\). Atomic number = 9, element is Fluorine (F).

Step3: Calculate total electrons for \(1s^2 2s^2 2p^6 3s^2 3p^2\)

Sum exponents: \(2 + 2 + 6 + 2 + 2 = 14\). Atomic number = 14, element is Silicon (Si).

Answer:

For \(1s^2 2s^2\): Beryllium (Be)
For \(1s^2 2s^2 2p^5\): Fluorine (F)
For \(1s^2 2s^2 2p^6 3s^2 3p^2\): Silicon (Si)