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name: gavin king (1000) q1 from assignments 1 & 2 (12 points) 1) write …

Question

name: gavin king (1000)
q1
from assignments 1 & 2 (12 points)

  1. write the following numbers in scientific notation (2 points, 1 point each) note: bold font was used to make it easier to count the 0s

a) 8,280
__________
b) 0.000048
__________

  1. write out the number the scientific - notation represents(2 points, 1 point each)

a) 3.14*10^5
__________
b) - 2.04*10^7
__________

  1. give the si unit for length______(1 point)
  2. using the conversion factor 2.2lbs = 1.0kg, convert my body weight of 185 pounds to si unit. show your work using the dimensional analysis format taught in class, you need to show units to get full credit. (3 points)
  3. density = mass/volume

you have a metal sample; you take measurements of 202 grams and 58 milliliters for the sample. what is the density of the metal sample?(1 point for the answer, 1 point for the units)

Explanation:

Step1: Convert to scientific notation for 8.280

Move decimal 0 places.
$8.280 = 8.28\times10^{0}$

Step2: Convert to scientific notation for 0.000048

Move decimal 5 places to the right.
$0.000048=4.8\times 10^{- 5}$

Step3: Expand $3.14\times10^{5}$

Multiply 3.14 by 100000.
$3.14\times10^{5}=314000$

Step4: Expand $- 2.04\times10^{7}$

Multiply - 2.04 by 10000000.
$-2.04\times10^{7}=-20400000$

Step5: SI unit for length

The SI unit for length is meter (m).

Step6: Convert 185 pounds to kg

Use conversion factor.
$185\ lbs\times\frac{1.0\ kg}{2.2\ lbs}=\frac{185}{2.2}\ kg\approx84.09\ kg$

Step7: Calculate density of metal sample

Use density formula $
ho=\frac{m}{V}$.
$
ho=\frac{202\ g}{58\ mL}\approx3.48\ g/mL$

Answer:

  1. a. $8.28\times10^{0}$

b. $4.8\times 10^{- 5}$

  1. a. 314000

b. - 20400000

  1. meter (m)
  2. 84.09 kg
  3. 3.48 g/mL